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3 years ago

The friction loss term is always a positive value O True O False No

Chemistry

1 answer:

lys-0071 [83]3 years ago

7 0

The answer will be true

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A 0.200 M solution of a weak acid, HA, is 9.4% ionized. Using this information, calculate Ka for HA.

slavikrds [6]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Initial concentration of weak acid HA = 0.200 M

and dissociation constant ( ${ \alpha}$ ) is :

$\qquad \sf \dashrightarrow \: \alpha = \frac{dissociation \: \: percentage}{100}$

$\qquad \sf \dashrightarrow \: \alpha = \frac{9.4}{100} = 0.094$

Now, at initial stage :

$\textsf{ Conc of HA = 0.200 M}$

$\textsf{Conc of H+ = 0 M}$

$\textsf{Conc of A - = 0 M}$

At equilibrium :

$\textsf{Conc of HA = 0.200 - 0.094(0.200) = 0.200(1 - 0.094) = 0.200(0.906) = 0.1812 M}$

$\textsf{Conc of H+ = 0.094(0.200) = 0.0188 M}$

$\textsf{Conc of A - = 0.094(0.200) = 0.0188 M}$

Now, we know :

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}}$

( big brackets represents concentration )

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}}$

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}}$

$\qquad \sf \dashrightarrow \: { K_a \approx 0.00195 }$

$\qquad \sf \dashrightarrow \: {K_a \approx 1.9 × {10}^{-3} }$

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2 years ago

What is the volume of gas at 2.00atm and 200.0K if its original volume was 300.0L at 0.25atm and 400.OK?

adell [148]

C because the volume of gas at 2.000 atm is 9.38L original volume was 3000l

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How is a cation different from a anion

masya89 [10]

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Contact [7]

Answer:

tetrafluorochlorate

Tetrafluorochlorate(1-)

PubChem CID60211070Molecular FormulaClF4-Synonymstetrafluorochlorate(1-) tetrafluoridochlorate(1-) F[Cl](F)(F)F ClF4(-) CHEBI:30125 More...Molecular Weight111.45 g/molDatesModify 2021-01-09 Create 2012-10-18

Explanation:

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4 years ago

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