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Galina-37 [17]
3 years ago
5

I NEED HELP ASAP, If you help me I’ll give you Brainlist [Calorimetry and specific heat lab]

Chemistry
2 answers:
Lyrx [107]3 years ago
6 0

Answer:

Explanation:

I gave this formula as

What you should get - what you got

---------------------------------------------------   * 100

What you should get

Suppose you are talking about the specific heat of copper and you did a lab and did it fairly well and the specific heat came out to be 0.33

That's what you got, 0.33

What you should get is 0.35 according to the table you've given us.

% error = 0.35 - 0.33

                -------------- * 100

                      0.35

% error = 0.02 * 100/ 0.35

% error = 2/0.35

% error = 5.71

Now here is the really hard part. You have to decide what a positive error is and what a negative error.

A positive error using this formula means you are too low.

A Negative error means that you are too high, just the opposite of what you might think.

Rina8888 [55]3 years ago
5 0

Can you show us the experimental value?

So basically, the accepted value would be under the Specific heat capacity of metal (e.g. 0.90, 0.35, 0.44, 0.12).

Your experimental value would be the specific heat capacity that you got from the lab.

You would first substract the experimental value from the accepted value

accepted \: value - experimental \: value

and then you would divide the result by the experimental value

result \div experimental \: value

and then, you would multiply the result of that by a hundred to get your percentage

result \times 100 = \% \: error

//

The image shown is an example.

0.90 is our accepted value.

0.88 is our experimental value.

The overall percentage error I got is %2.27

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