Answer:
Explanation:
The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
Kp is defined as the ratio of pressure of products and pressure of reactants:
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A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
1 answer:
Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m) = 16.59 g
Volume (v) = 5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:
Substitute the values into the formula:
= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.
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Explanation:
The net equation will be as follows.
So, we are required to find for this reaction.
Therefore, steps involved for the above process are as follows.
Step 1: Convert K from solid state to gaseous state
,
= 89 kJ
Step 2: Ionization of gaseous K
,
= 418 KJ
Step 3: Dissociation of gas into chlorine atom
.
,
= 122 KJ
Step 4: Iozination of chlorine atom.
,
= -349 KJ
Step 5: Add ion and
ion formed above to get KCl
.
,
= -717 KJ
Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.
= 89 + 418 + 122 - 349 - 717
= - 437 KJ/mol
Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.