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3 years ago

2y (4 - x) = x/2 where x= 2

1 answer:

5 0

Hello!

2y(4-x)=x/2

[plug in 2 for x] 
2y(4-2)=2/2 

[4-2 is 2, 2/2 is 1] 
2y(2)=1 

[divide both sides by 2] 
2y=1/2 

[divide by 2 again] 
y=1/4

====>So As Result As We See, y = 1/4.<====

Hope this Helps! Have A WONDERFUL Rest Of Your Day! :)

(Ps. Don't Forget To Mark As BRAINLIEST!)

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Read 2 more answers

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2 Express answer as a common fraction. Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

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3 years ago