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3 years ago

What is the equation of the line that passes through (-1,-6) and has a slope of 1

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Answer:

x-y-5=0

Step-by-step explanation:

x+1=1*(y+6)

x+1=y+6

x-y-5=0

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Can someone please help me on these two questions tysm

Rashid [163]

Plug them in:

x + 5y = 18
x - 3y = 10

F. (1,13)
G. (13,1)
H. (-2,4)
J. (-2,-4)

1 + 5*13 = 18 is obliviously not true so that takes out the first option.

13 + 5*1 = 18 : This is true but we have to check the next one.
13 - 3*1 = 10 : This is also true so we know this is the answer. We don't really need to check the other 2 but u can if u want to.

Hope that helped :)

8 0

3 years ago

Someone help please!

saveliy_v [14]

Answer:

BC ≈ 14.7 m

Step-by-step explanation:

Using the Sine rule in Δ ABC

$\frac{AB}{sinC}$ = $\frac{BC}{sinA}$

To find ∠ A subtract the 2 given angles from 180°

∠ A = 180° - (90 + 28)° = 180° - 118° = 62°

Then

$\frac{7.8}{sin28}$ = $\frac{BC}{sin62}$ ( cross- multiply )

BC × sin28° = 7.8 × sin62° ( divide both sides by sin28° )

BC = $\frac{7.8sin62}{sin28}$ ≈ 14.7 m ( to 3 significant figures )

5 0

3 years ago

What is the slope of the line !?!?!

Sergeu [11.5K]

Answer:

Slope is -2

Step-by-step explanation:

8 0

3 years ago

Solve by using square root: 4(x-1)^2+2=10

Scilla [17]

$4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}$

$Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}$

3 0

4 years ago

Read 2 more answers

Solve: 4 = k/7 a. 24 b.11 c. 32 d. 28

Margarita [4]

Answer:

D. 28

Step-by-step explanation:

$4 = \frac{k}{7} \\\\28 = k$

8 0

4 years ago

Read 2 more answers