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SOVA2 [1]
3 years ago
8

Mr. Jones' recipe calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day?

Mathematics
1 answer:
dsp733 years ago
5 0

Due to the fact that no one can consume .04 of a tablet, we can round down this answer to 1. Even if we were told to round to the tens place, we would still be unable. Remember, 5 or above, give it a shove, 4 or below, let it go. This means that Mr. Jones should take C- 1 tablet per day.

I hope I've helped! :)

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if you have 35 and you're friend gives you 35 more then someone takes 15 then you give 10 away and you ate 19 then you're friend
emmainna [20.7K]

49.

35+35-15-10-19+23 is 49.

8 0
3 years ago
What are the zeros of the polynomial function f(x)=x^3-2x^2-8x?
Rashid [163]

Answer: -2, 0, 4

Set the equation equal to zero.

x³ - 2x² - 8x = 0

Factor out x in the equation, since all the terms (x³, -2x², and -8x) are divisible by x. You can check your accuracy using the Distributive Property.

x(x² - 2x - 8) = 0

Factor out the polynomial. To do this, find two numbers that multiply to get the last term, -8, and add together to get the middle term, -2. In this case, those two numbers are -4 and 2 (-4 × 2 = -8 and -4 + 2 = -2). Don't forget about the x that was factored out before!

x(x - 4)(x + 2) = 0

Set each factor equal to zero and solve for x. The factors in the equation are x, (x - 4), and (x + 2).

  • x = 0
  • (x - 4) = 0

        x = 4

  • (x + 2) = 0  

        x = -2

The zeros of the polynomial function are -2, 0, and 4.

3 0
3 years ago
1/4 Marks
rusak2 [61]

Answer:

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Step-by-step explanation:

a) 24.58

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c) 58.99

d) 0.98

3 0
3 years ago
Read 2 more answers
Rationalize the denominator of \frac{1 \sqrt{3}}{1-\sqrt{3}}. When you write your answer in the form A B\sqrt{C}, where A, B, an
kobusy [5.1K]

Answer:

The value of ABC is 6.

Step-by-step explanation:

Consider the expression

\frac{1+\sqrt{3}}{1-\sqrt{3}}

Rationalize the denominator.

\frac{1+\sqrt{3}}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}

\frac{(1+\sqrt{3})^2}{1^2-(\sqrt{3})^2}

\frac{1^2+(\sqrt{3})^2+2\sqrt{3}}{1-3}

\frac{1+3+2\sqrt{3}}{-2}

\frac{4+2\sqrt{3}}{-2}

\frac{4}{-2}+\frac{2\sqrt{3}}{-2}

-2-\sqrt{3}              ..... (1)

The answer in the form

A+B\sqrt{C}           .... (2)

On comparing (1) and (2), we get

A=-2,B=-1,C=3

We need to find the value of ABC.

ABC=(-2)(-1)(3)=6

Therefore the value of ABC is 6.

7 0
3 years ago
Which figure is a unit square?
photoshop1234 [79]

Answer:

C

Step-by-step explanation:

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2 years ago
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