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3 years ago

12

Practice: Organizing Information

1 answer:

Morgarella [4.7K]3 years ago

4 0

${(b^n)}^m=b^{nm} \\ \\ {(5^2)}^3=5^{6} \\ \\$

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Multiply: Using FOIL method<br> (x-8)^3

alukav5142 [94]

(x - 8)³
(x - 8)(x - 8)(x - 8)
(x² - 8x - 8x + 64)(x - 8)
(x² - 16x + 64)(x - 8)
(x³ - 8x² - 16x² + 128x + 64x - 512)
x³ - 24x² + 192x - 512

6 0

3 years ago

PLZZ I NEED HELP if ur good at math help meeee. I NEED HELP

Ilya [14]

It looks like it’s already answered I’m confused about that

4 0

2 years ago

Can someone please help

Alika [10]

Answer:

option (B).

Step-by-step explanation:

it's really simple....

just replace the (n) near the 3 with 1,2,3,4,5 and 6 and then solve the maths and when you're done , you add the answers all up.

sooo...

3(1)-2 = 1

3(2)-2 = 4

3(3)-2 = 7

3(4)-2 = 10

3(5)-2 = 13

3(6)-2 = 16

now we add them all up...

1+4+7+10+13+16 = <u>5</u><u>1</u><u>.</u>

Hope this helps.

Good luck.

3 0

2 years ago

I need the answer to this help?

7nadin3 [17]

Answer:

x = 20

You do 120 + 3x = 180

It's same-side interior.

5 0

2 years ago

PLEASE HURRY!! WILL GIVE BRAINLIEST

inysia [295]

Trigonometric ratios are useful in calculating the side lengths of a triangle.

The length of the zip line is 222.5 ft
The height where the ladder rests against the tree is 38.6 ft
The distance between the base of the ladder and that of the tree is 10.4 ft
The distance between the base of the tree and the spot where the zip line is anchored to the ground is 219.1 ft

<u>(a) Length, z</u>

First we calculate (h) using the following sine ratio

$\mathbf{sin(75) = \frac{h}{40}}$

Make h the subject

$\mathbf{h = 40sin(75)}$

Next, we calculate (z) using the following sine ratio

$\mathbf{sin(10)= \frac{h}{z}}$

Make z the subject

$\mathbf{z= \frac{h}{sin(10)}}$

Substitute $\mathbf{h = 40sin(75)}$

$\mathbf{z= \frac{40sin(75)}{sin(10)}}$

$\mathbf{z= 222.5 ft}$

Hence, the length of the zip line is 222.5 ft

<u>(b) The height, h</u>

In (a), we have

$\mathbf{h = 40sin(75)}$

Evaluate

$\mathbf{h = 38.6}$

Hence, the height where the ladder rests against the tree is 38.6 ft

<u />

<u>(c) The distance, b</u>

To do this, we make use of the following sine ratio

$\mathbf{sin(15) = \frac{b}{40}}$

Make b the subject

$\mathbf{b = 40sin(15)}$

$\mathbf{b = 10.4}$

Hence, the distance between the base of the ladder and that of the tree is 10.4 ft

<u />

<u>(d) Distance, B</u>

To do this, we make use of the following sine ratio

$\mathbf{sin(80) = \frac{B}{z}}$

Make B the subject

$\mathbf{B = z\ sin(80)}$

Substitute $\mathbf{z= 222.5 ft}$

$\mathbf{B = 222.5\ sin(80)}$

$\mathbf{B = 219.1}$

Hence, the distance between the base of the tree and the spot where the zip line is anchored to the ground is 219.1 ft

<u />

Read more about trigonometry ratios at:

brainly.com/question/24888715

8 0

3 years ago