Answer:
85.5 minutes
Step-by-step explanation:
The amount of an element that will remain after time t can be expressed as a function of initial amount N0, time t, and half life th as;
Nt = N0 × e^(-λt)
Where;
Decay constant λ = ln(2)/th, substituting into the equation;
Nt = N0 × e^(-ln(2)t/th)
We need to make t the subject of formula;
Nt/N0 = e^(-ln(2)t/th)
ln(Nt/N0) = -ln(2)t/th
t = ln(Nt/N0) ÷ -ln(2)/th
Given;
Initial amount N0 = 760g
Final amount Nt = 11 g
Half life th = 14 minutes
the nearest tenth of a minute, would it take the element to decay to 11 grams can be derived using the formula;
t = ln(Nt/N0) ÷ -ln(2)/th
Substituting the given values;
t = ln(11/760) ÷ -ln(2)/14
t = 85.5 minutes
Answer:
Step-by-step explanation:
buys it for $ 45
well...you know the business is gonna want to make a profit...so they would have to sell it for more then they bought it for.
I would say $ 60 or $ 80
Step 1: Put the numbers in order.
1,2,5,6,7,9,12,15,18,19,27<span>Step 2: </span>Find the median (How to find a median).
1,2,5,6,7,9,12,15,18,19,27<span>Step 3: </span>Place parentheses around the numbers above and below the median.
Not necessary statistically–but it makes Q1 and Q3 easier to spot.
(1,2,5,6,7),9,(12,15,18,19,27)<span>Step 4: </span>Find Q1 and Q3
Q1 can be thought of as a median in the lower half of the data. Q3 can be thought of as a median for the upper half of data.
(1,2,5,6,7), 9, ( 12,15,18,19,27). Q1=5 and Q3=18.<span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
18-5=13.
Hope this helped:)
-BRIEMODEE:)
