Answer:
1
Step-by-step explanation:
Co-efficient means the integer in front of the variable
The co-efficient for -4x^3 would be -4 like that
Beginning with the function y = sin x, which would have range from -1 to 1 and period of 2pi:
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.
Wow this is a doozy! First you have to figure out what is it you are looking for? If you make a dot in the center of the triangle (which is also the center of the circle) and draw a line from the center to one of the vertices of the triangle you have the radius of the triangle and also of the circle. If you draw all 3 radii from the triangle's center to its vertices, you see you have created 3 triangles within that one triangle. The trick here is to figure out what your triangle measures are as far as angles go. If we take the interior measures of those 3 triangles, we get that each one has a measure of 120 (360/3=120). So that's one of your angles, the one across from the side measuring 6. Because of the Isosceles Triangle theorem, we know that the 2 base angles have the same measure because the sides are the same. Subtracting 120 from 180 gives you 60 which, divided in half, makes each of those remaining angles measure 30 degrees. So if we extract that one triangle from the big one, we have a triangle with angles that measure 30-30-120, with the base measuring 6 and each of the other sides measuring 5. If we then split that triangle into 2 right triangles, we have one right triangle with measures 30-60-90. Dropping that altitude to create 2 right triangles not only split the 120 degree angle at the top in half, it also split the base side of 6 in half. So our right triangle has a base of 3 and we are looking for the hypotenuse of that right triangle. WE have to use right triangle trig for that. Since we have the top angle of 60 and the base of 3, we can use sin60=3/x. Solving for x we have x=3/sin60 which gives us an x value of 3.5 inches rounded from 3.464. I'm not sure what you mean by a mixed number unless you mean a decimal, but that's the radius of that circle.
Answer:
210 cm²
Step-by-step explanation:
The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.
Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles
✔️Area of the 2 trapezoid bases:
Area = 2(½(a + b)×h)
Where,
a = 7 cm
b = 11 cm
h = 3 cm
Plug in the values
Area = 2(½(7 + 11)×3)
= (18 × 3)
Area of the 2 trapezoid bases = 54 cm²
✔️Area of Rectangle 1:
Length = 6 cm
Width = 3 cm
Area = 6 × 3 = 18 cm²
✔️Area of Rectangle 2:
Length = 7 cm
Width = 6 cm
Area = 7 × 6 = 42 cm²
✔️Area of Rectangle 3:
Length = 6 cm
Width = 5 cm
Area = 6 × 5 = 30 cm²
✔️Area of Rectangle 4:
Length = 11 cm
Width = 6 cm
Area = 11 × 6 = 66 cm²
✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
__
(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
__
(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
