Given the graph below, which of the following statements is true?

PLEASE HELP ME, FIRST ANSWER WILL GET BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Bumek [7]

11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13

12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x

X=2
TU= 7
UB= 3
TB=10

Problem 13:

2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84

Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49

5 0

2 years ago

bob has 64 cups. could he distribute them into 6 equally in stacks and not have any left over? Explain

Iteru [2.4K]

Bob cannot distribute the cups in six equal stacks and not have any left over.

Step-by-step explanation:

In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.

So

Dividing 64 by 6

$= \frac{64}{6} \\= 10\frac{4}{6}$

Here

Quotient = 10

Remainder = 4

As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.

Keywords: Division, fractions

Learn more about division at:

#LearnwithBrainly

8 0

2 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago

I will give u brainselst if u solve question below plz show work....

GalinKa [24]

Answer:

26 inches

Step-by-step explanation:

4 0

2 years ago

How do you find the lease common fatcor

8_murik_8 [283]

Answer:

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

Step-by-step explanation:

4 0

3 years ago