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2 years ago

A a migrating bird flies 384 miles in 12 hours how many hours does it flies in 5 hours

Mathematics

1 answer:

shusha [124]2 years ago

4 0

Divide 384 by 12 then multiply it by 5 to give you 160

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Given that 6x – 5y = 14<br>Find x when y = 2

Sloan [31]

Answer:

x = 4

Step-by-step explanation:

Given

6x - 5y = 14 ← substitute y = 2 into the equation

6x - 5(2) = 14

6x - 10 = 14 ( add 10 to both sides )

6x = 24 ( divide both sides by 6 )

x = 4

4 0

2 years ago

Read 2 more answers

Sam buys 4 boxes of the Crispy Crunch Cereal at Store A. What fraction of the original price of each box of cereal does he pay p

Step2247 [10]

Answer:

Step-by-step explanation:

8 0

3 years ago

About how much difference in average leaf width would you find in two forests whose average annual rainfalls are near 1500 mm bu

goblinko [34]

Answer:

4.80 mm to 2 d.p

Step-by-step explanation:

w = f(r)

f'(r) = (dw/dr) = (0.0218 mm/mm)

So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.

One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.

Mathematically,

(dw/dr) = (Δw/Δr) for very small Δw and Δr.

0.0218 = (Δw/220)

Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p

Hope this Helps!!!

5 0

3 years ago

Which expression is the radical form of m to the power of -0.3333

Evgen [1.6K]

Answer:

A1/ ∛m

Step-by-step explanation:

m ^ (-1/3)

this is m to the cubed root in the denominator

1/ ∛m

8 0

3 years ago

find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on

enyata [817]

Let $f(x)=\tan^{-1}x$ . Then $f'(x)=\frac1{1+x^2}$ . Note that $f(0)=0$ .

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

This means that for $|-x^2|=|x|^2$ , or $-1$ , we have

$\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}$

Integrate the series to get

$f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

$\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

6 0

3 years ago