To balance a half-reaction in basic solution, you need to add enough of which substances to balance the equation?

1 answer:

5 0

In balancing half-reactions, it is important to know if the medium is basic or acidic. For basic medium, what is added to the reactant side is the hyroxide ion OH- and what is added to the other side is H2O. The answer is the fifth option.

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Under the same conditions of temperature and pressure how does a liquid differ from a gas

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An airplane began with an initial velocity of 120 m/s and ended with a final velocity of 180 m/s in 4 seconds. What was its acce

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Name the type of chemical bonding in potassium bromide

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A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w

Serhud [2]

Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

$A = 50*929,0304$

$\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)$

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

$m = 8,5*28,3495$

$\boxed{m = 240,97075\:g}\Longleftarrow(mass)$

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}$

$V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}$

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

$V (volume) = A (Area) * T (Thickness)$

$89,25\:cm^3 = 46451,52\:cm^2\:*\:T$

$46451,52\:cm^2*T = 89,25\:cm^3$

$T = \dfrac{89,25\:cm^3}{46451,52\:cm^2}$

$T = 0,001921358009...\:cm$

We will convert to millimeters, going through a decimal place on the right

$T = 0,01921358009..\:mm$

$\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark$

Hope this helps! :))

8 0

3 years ago

The theoretical yield of NH3 is 945 grams. You conducted the experiment and only produced 598 grams.

zlopas [31]

Answer:

Given theoretical yield of NH3 is 945g.

The actual yield is 598g.

What is the %yield?

Explanation:

%yield of a chemical reaction can be calculated by using the formula:

$%yield=\frac{actual yield}{theoretical yield} * 100$ $\frac{actual yield}{theoretical yield} * 100$