The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days
<h3>How to determine the number of half-lives </h3>
- Original amount (N₀) = 98.3 micrograms
- Amount remaining (N) = 12.3 micrograms
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 98.3 / 12.3
2ⁿ = 8
2ⁿ = 2³
n = 3
<h3>How to determine the half life </h3>
- Number of half-lives (n) = 3
- Time (t) = 414 days
- Half-life (t½) = ?
t½ = t / n
t½ = 414 / 3
t½ = 138 days
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Answer:
1. ![R=k[A]^1[B]^2](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E2)
2. ![R=k[B]^1](https://tex.z-dn.net/?f=R%3Dk%5BB%5D%5E1)
3. ![R=k[A]^0[B]^0=k](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E0%3Dk)
4. ![R=k[A]^1[B]^{-1}](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E%7B-1%7D)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
(1) is second order in B and overall third order.
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= x + 2 = 3
x = 1
Rate of the reaction =R
![R=k[A]^1[B]^2](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E2)
(2) is zero order in A and first order in B.
2A + B → C
Rate of the reaction =R
![R=k[A]^0[B]^1=k[B]^1](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E1%3Dk%5BB%5D%5E1)
Order of the reaction = sum of stoichiometric coefficient
= 0 + 1 = 1
(3) is zero order in both A and B .
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= 0 + 0 = 0
Rate of the reaction =R
![R=k[A]^0[B]^0=k](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E0%3Dk)
(4) is first order in A and overall zero order.
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= 1 + x = 0
x = -1
Rate of the reaction = R
![R=k[A]^1[B]^{-1}](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E%7B-1%7D)
Answer:
The answer is wave B, wave A
Explanation:
The closer the waves the higher the pitch. The higher the waves the louder it is.