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Harlamova29_29 [7]
1 year ago
8

you are given a solution of lead nitrate. use any of the solution used in this experiment to form a white precipitate of lead ch

loride. write down the equation
Chemistry
1 answer:
Vesnalui [34]1 year ago
7 0

We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.

If a chlorine solution is used we will have the following reaction:

Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3

So, with a chlorine solution, we will have a white precipitate of lead chloride.

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An increase in the atomic number________the atomic radius moving from left to right across a period.
frez [133]

Answer:

decrease

Explanation:

Atomic radius :

It is the distance from the center of nucleus to the outer most electronic shell.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required

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3 years ago
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Svetach [21]

Answer:

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3 years ago
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Vsevolod [243]
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schepotkina [342]

Answer:

\rm ^{103}_{\phantom{1}40}Zr, zirconium-103.

Explanation:

In a nuclear reaction, both the mass number and atomic number will conserve.

Let ^{A}_{Z}\mathrm{X} represent the unknown particle.

The mass number of a particle is the number on the upper-left corner. The atomic number of a particle is the number on its lower-left corner under the mass number. For example, for the particle ^{A}_{Z}\mathrm{X}, A is the mass number while Z while Z is the atomic number.

Sum of mass numbers on the left-hand side of the equation:

\underbrace{239}_{^{239}_{\phantom{2}94}\mathrm{Pu}} + \underbrace{1}_{^{1}_{0}\mathrm{n}} = 240.

Note that there are three neutrons on the right-hand side of the equation. Sum of mass numbers on the right-hand side:

\underbrace{A}_{^{A}_{Z}\mathrm{X}} + \underbrace{134}_{^{134}_{\phantom{2}54}\mathrm{Xe}} + \underbrace{3\times 1}_{3\;^{1}_{0}\mathrm{n}} = A + 137.

Mass number conserves. As a result,

A + 137 = 240.

Solve this equation for A:

A = 103.

Among the five choices, the only particle with a mass number of 103 is \rm ^{103}_{\phantom{1}40}Zr. Make sure that atomic number also conserves.

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