The dissociation reaction of acetic acid is as follows:

The acid dissociation constant K_{a} is
.
Let the initial concentration of acid be A, and concentration of
and
be zero.
After dissociation, concentration of acid becomes A-x and that of both
and
becomes x.
Expression for acid dissociation constant will be:
![K_{a}=\frac{[CH_{3}COO^{-}][H^{+}]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D)
pH of solution is 3.5, thus, concentration of hydrogen ion can be calculated as follows:
![pH=-log[H^{+}]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%7B%2B%7D%5D)
On rearranging,
![[H^{+}]=10^{-pH}=10^{-3.5}=0.0003162](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-3.5%7D%3D0.0003162)
Since,
Thus,
![[CH_{3}COO^{-}]=0.0003162](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%3D0.0003162)
and, 
Putting the values, in expression for acid dissociation constant,
![1.76\times 10^{-5}=\frac{(0.0003162)(0.0003162)}{[CH_{3}COOH]_{initial}-0.0003162}](https://tex.z-dn.net/?f=1.76%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%280.0003162%29%280.0003162%29%7D%7B%5BCH_%7B3%7DCOOH%5D_%7Binitial%7D-0.0003162%7D)
On rearranging,
![[CH_{3}COOH]_{initial}=\frac{(0.0003162)\times (0.0003162)}{1.76\times 10^{-5}}+0.0003162=0.006](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOOH%5D_%7Binitial%7D%3D%5Cfrac%7B%280.0003162%29%5Ctimes%20%280.0003162%29%7D%7B1.76%5Ctimes%2010%5E%7B-5%7D%7D%2B0.0003162%3D0.006)
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<span> the equation for helium could be: D + T -> He + n. D is deuterium (H-2), T is tritium (H-3), and n symbolizes a neutron.</span>
Answer:
It is believed that the stability of an isotope is based on the ratio of neutrons to protons.
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Answer:
<em>Proteins, carbohydrates, nucleic acids, and lipids are the four major classes of biological macromolecules—large molecules necessary for life that are built from smaller organic molecules. Macromolecules are made up of single units known as monomers that are joined by covalent bonds to form larger polymers.</em>
Explanation:
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