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Sedaia [141]
3 years ago
10

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the stand

ard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2
Mathematics
1 answer:
Natalija [7]3 years ago
4 0

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{1-(-3)}{12-(-4)}=\dfrac{4}{16}=\dfrac{1}{4}

Correct equation of the line is

y-1=\dfrac{1}{4}(x-12)

The standard form is: Ax + By = C.

y-1=\dfrac{1}{4}(x-12)\qquad|\text{use distributive property}\\\\y-1=\dfrac{1}{4}x-3\qquad|\text{multiply both sides by 4}\\\\4y-4=x-12\qquad|\text{add 12 to both sides}\\\\4y+8=x\qquad|\text{subtract 4y from both sides}\\\\8=x-4y

<h3>Answer: x - 4y = 8</h3>
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