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Schach [20]
3 years ago
9

What number must you add to the polynomial below to complete the square? x^2+17x

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

The number added to the polynomial by completing the square is \frac{289}{4}

Explanation:

Given that the polynomial is x^{2} +17x

We need to determine the number that is added to the polynomial to complete the square.

The last term of the polynomial can be determined by dividing the term 17 by 2 and then squaring the term.

Thus, we have,

Last term = \frac{17}{2}

Now, squaring the term, we have,

Last term = (\frac{17}{2})^2=\frac{289}{4}

Thus, the number added to the polynomial by completing the square is \frac{289}{4}

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Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
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Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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