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Lemur [1.5K]
3 years ago
12

Lemon juice has a pH of about 2.0, compared with a pH of about 1.0 for stomach acid. Therefore, the concentration of H+ in stoma

ch acid is __________ than that of lemon juice.
Chemistry
2 answers:
Tanzania [10]3 years ago
7 0

Answer:

The concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.

Explanation:

LuckyWell [14K]3 years ago
5 0

Answer:

The concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.

Explanation:

The H⁺ concentration of a solution is exponentially related to its pH value:

\rm [H^{+}] = 10^{-pH}.

For lemon juice:

\rm [H^{+}] = 10^{-2.0} = 0.01\; M.

For stomach acid:

\rm [H^{+}] = 10^{-1.0} = 0.1\; M.

Thus, the concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.

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Integrated rate law for second order unimolecular irreversible
kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}

rearranging the ecuation

-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}

Integrating between times 0 to <em>t </em>and between the concentrations of [A]_{0} to <em>[A].</em>

\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}

Solving the integral

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

5 0
3 years ago
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
OLEGan [10]

Answer:

16 Molarity

Step-by-step:

M= mols/L

M= 8mols/.5L

M= 16 Molarity

7 0
3 years ago
Read 2 more answers
According to reference table adv-10, which is the strongest reducing agent?
Mumz [18]
Li(s)    (answer  A)   
    Li  is  strongest  reducing  agent  because  of  the   lowest  standard reduction  potential.  when  something  is  oxidized, it  reduces  another  substance,  becoming a  reducing.Hence  Lithium  is  strongest  reducing  agent. Reducing  agent   is  stronger  when  it  has  a  more  positive  oxidation potential.
3 0
3 years ago
If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

6 0
3 years ago
Consider the following weak acids and their Ka values: Acetic Acid Ka = 1.8×10^−5 Phosphoric Acid Ka = 7.5×10^−3 Hypochlorous Ac
vfiekz [6]

Answer:

a. Phosphoric Acid

b. Acetic Acid

c. Hypochlorous Acid

Explanation:

A buffer works when the pH of this one is in pKa ± 1. That means, to find which buffer system works in some pH you need to find pKa:

pKa = -log Ka

<em>pKa Acetic acid:</em>

-log1.8x10⁻⁵ = 4.74

<em>pKa phosphoric acid:</em>

-log7.5x10⁻³ = 2.12

<em>pKa hypochlorous acid:</em>

-log3.5x10⁻⁸ = 7.46

a. For a pH of 2.8 the best choice is phophoric acid because its effective range is: 1.12 - 3.12 and 2.8 is between these values.

b. pH 4.5. Acetic acid. effective between pH's 3.74 - 5.74

c. pH 7.5. Hypochlorous acid that works between 6.46 and 8.46

7 0
3 years ago
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