Answer: sexual reproduction results to the offspring having a mix of genetic characteristics of the parents. Where as Asexual offspring tend to look like their parent.
Explanation:
Intercourse leads to the mixing of genetic material. Asexual reproduction is often the parent making a separate copy of themselves.
Answer:
a. The new pressure is 606,25 Torr.
b. -243,9°C is needed to reach the pressure of 7250 Torr.
Explanation:
Gay Lussac's law for gases says that if the volume in a gas remains constant, the pressure will be directly proportional to the temperature change.
P1 . T1 = P2. T2
(Temperature must be in K)
725 Torr . 291 K = P2 . 348 K
(725 Torr . 291 K) /348 K = P2
606,25 Torr = P2
725 Torr . 291K = 7250 Torr . T2
(725 Torr . 291K) /7250 Torr = T2
29,1 K = T2
T° K - 273 = T°C
29,1 K -273 = -243,9°C
Answer:
Carbon-14 has a half life of 5730 years. This means it takes 5730 years for half of the carbon-14 atoms to decay to carbon-12 in a given sample (eg: 100 carbon-14, one half life = 50 carbon-14, 50 carbon-12).
Explanation:
<u>Answer:</u>
<u>For (i):</u> Magnesium is getting oxidized and zinc is getting reduced.
<u>For (ii):</u> The half reactions are given below.
<u>For (iii):</u> Magnesium will act as anode and zinc act as cathode.
<u>Explanation:</u>

The substance having highest positive
potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.
Magnesium will undergo oxidation reaction and will get oxidized.
Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

Oxidation half reaction: 
Reduction half reaction: 
Oxidation reaction always occurs on anode side and thus, magnesium is acting as anode.
Reduction reaction always occurs on cathode side and thus, zinc is acting as cathode.
Al(OH)3 + 3HBr -> AlBr3 + 3H2O
<span>Al(OH)3 is a solid, HBr is aqueous, AlBr3 is aqueous and H2O is liquid.
</span>
<span>Ionic Equation </span>
<span>Al(OH)3 + 3H^+ -> Al^3+ + 3H2O</span>