I cannot see your picture, but if the plane cutting the cylinder is indeed perpendicular to the cylinder's base, then the cross section must be square or rectangular. Going by the shape of most cylinders, I would guess that it is rectangular.
Answer:
y = 3(x - 4)²
Step-by-step explanation:
Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
3848,451001
Step-by-step explanation:
A = πr²
A = π[35]²
A = 1225π
A = 3848,451001
I hope this is correct, and as always, I am joyous to assist anyone at any time.