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Sholpan [36]
3 years ago
7

A technician is working at a client's office after hours and needs two cables to finish the work but does not have immediate acc

ess to prebuilt cables. One cable needed is for a dial-up connection from the dial-up modem to the existing analog POTS jack on the wall. The other cable is for an Ethernet connection from the computer to the existing keystone jack on the wall. The technician has the necessary wire and connectors to make the cables. Which of the following tools will the technician use to make the cables and then verify that they both work properly? (Select THREE.)
Computers and Technology
1 answer:
svetlana [45]3 years ago
3 0

Answer:

The following are the answers of the given scenario.

  • Crimper
  • Cable tester
  • Cable stri.pper

Explanation:

After hours, the specialist operates at that same customer's workplace as well as wants several wires to complete the job, although it would not provide direct links for pre-built wires. The wire required seems to be a dial-up link from the dial-up network to an original analog POTS port on a wall. Another wire would be to attach an Ethernet from the device to that of the current keystone port on that same wall.

Thus, Crimper, Cable Tester and Cable Stri.pper are the same equipment that the specialist needs to use to create the wires as well as then check whether these all operate correctly.

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Mice21 [21]

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6 0
3 years ago
A(n) __________ port, also known as a monitoring port, is a specially configured connection on a network device that is capable
drek231 [11]

Answer:

The answer is "SPAN"

Explanation:

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7 0
3 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0
3 years ago
When was technology created?
ANEK [815]

Answer:

two million years ago

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3 0
1 year ago
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