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Sholpan [36]
3 years ago
7

A technician is working at a client's office after hours and needs two cables to finish the work but does not have immediate acc

ess to prebuilt cables. One cable needed is for a dial-up connection from the dial-up modem to the existing analog POTS jack on the wall. The other cable is for an Ethernet connection from the computer to the existing keystone jack on the wall. The technician has the necessary wire and connectors to make the cables. Which of the following tools will the technician use to make the cables and then verify that they both work properly? (Select THREE.)
Computers and Technology
1 answer:
svetlana [45]3 years ago
3 0

Answer:

The following are the answers of the given scenario.

  • Crimper
  • Cable tester
  • Cable stri.pper

Explanation:

After hours, the specialist operates at that same customer's workplace as well as wants several wires to complete the job, although it would not provide direct links for pre-built wires. The wire required seems to be a dial-up link from the dial-up network to an original analog POTS port on a wall. Another wire would be to attach an Ethernet from the device to that of the current keystone port on that same wall.

Thus, Crimper, Cable Tester and Cable Stri.pper are the same equipment that the specialist needs to use to create the wires as well as then check whether these all operate correctly.

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True is the correct answer for the above question.

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Question 2 In this question you are asked to calculate probabilties for the discrete uniform and exponential distribution. Make
sasho [114]

Answer:

Hi there! The question is asking to make changes to the H3_Q2.java program however there is no such program attached. Nevertheless, the requirements in the question can be addressed in a new H3_Q2.java program that i've listed below.

Explanation:

We can use the Scanner util in Java for prompting user input. The method nextInt() and nextDouble() allow only values of types "int" and "double" respectively. I have used the "switch" statement to direct the program based on user selection of menu item. The checks are printed with the "System.out.println" command and the program exits in case of error or invalid input. Finally, the calculation of probability simply requires you to replace the comment with the formula for the probability calculation based on the method chosen.

H3_Q2.java

import java.util.Scanner;

public class H3_Q2 {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please type 1 to select 'discrete uniform' or 2 to select 'exponential'");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   switch(selection) {

     case 1:

       // discrete uniform

       System.out.println("Please enter a lower bound value a: ");

       int a = scan.nextInt();

       System.out.println("Please enter a upper bound value b: ");

       int b = scan.nextInt();

       System.out.println("Please enter a value x: ");

       int x = scan.nextInt();

       if (b <= a) {

         System.out.println("The upper bound value b should be greater than the lower bound value a");

         System.exit(0);

       }

       if (a > x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       if (b < x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       break;

     case 2:

       // exponential

       System.out.println("Please enter a lambda value for exponential: ");

       double lambda = scan.nextDouble();

       System.out.println("Please enter a value x: ");

       double d_x = scan.nextDouble();

       if (d_x <= 0.0) {

         System.out.println("The value x should be greater than 0");

         break;

       } else {

         // calculate P(X = x) and P(X ≤ x)

         // result = calculateExponential()

         System.out.println("The calculation for the exponential method given the lambda value " + lambda + " and the value of x " + d_x + " is: ");

       }

       break;

     default:

       System.out.println("Invalid input. Exiting..");

       break;

   }

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}

7 0
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Write a c program to print all possible marking schemes of 15 questions each with 3.
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Answer:

#include <math.h>

#include <stdio.h>

#include <string.h>

#define BASE 3

#define NRQUESTIONS 15

void toABC(int n, char* buf, int base, int size) {

   memset(buf, 'A', size);

   buf[size] = 0;

   while (n && size) {

       buf[--size] = 'A' + (n % base);

       n /= base;

   }    

}

int main()

{

   char buf[16];

   for (int i = 0; i < pow(BASE, NRQUESTIONS); i++) {

       toABC(i, buf, BASE, NRQUESTIONS);

       printf("%s\n", buf);

   }

}

Explanation:

Assuming 3 is the number of possible answers to choose from for each question.

I tackled this by having an integer counter enumerate all values from 0 to 3^15, and then convert each integer to a base-3 representation, using ABC in stead of 012.

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