The square 8 units is above the grid for stage. Coordinations was the location
The solution depends on the value of
![k](https://tex.z-dn.net/?f=k)
. To make things simple, assume
![k>0](https://tex.z-dn.net/?f=k%3E0)
. The homogeneous part of the equation is
![\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D-16ky%3D0)
and has characteristic equation
![r^2-16k=0\implies r=\pm4\sqrt k](https://tex.z-dn.net/?f=r%5E2-16k%3D0%5Cimplies%20r%3D%5Cpm4%5Csqrt%20k)
which admits the characteristic solution
![y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}](https://tex.z-dn.net/?f=y_c%3DC_1e%5E%7B-4%5Csqrt%20kx%7D%2BC_2e%5E%7B4%5Csqrt%20kx%7D)
.
For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be
![y_p=ae^{4x}+be^x](https://tex.z-dn.net/?f=y_p%3Dae%5E%7B4x%7D%2Bbe%5Ex)
. Then
![\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y_p%7D%7B%5Cmathrm%20dx%5E2%7D%3D16ae%5E%7B4x%7D%2Bbe%5Ex)
So you have
![16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x](https://tex.z-dn.net/?f=16ae%5E%7B4x%7D%2Bbe%5Ex-16k%28ae%5E%7B4x%7D%2Bbe%5Ex%29%3D9.6e%5E%7B4x%7D%2B30e%5Ex)
![(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x](https://tex.z-dn.net/?f=%2816a-16ka%29e%5E%7B4x%7D%2B%28b-16kb%29e%5Ex%3D9.6e%5E%7B4x%7D%2B30e%5Ex)
This means
![16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}](https://tex.z-dn.net/?f=16a%281-k%29%3D9.6%5Cimplies%20a%3D%5Cdfrac3%7B5%281-k%29%7D)
![b(1-16k)=30\implies b=\dfrac{30}{1-16k}](https://tex.z-dn.net/?f=b%281-16k%29%3D30%5Cimplies%20b%3D%5Cdfrac%7B30%7D%7B1-16k%7D)
and so the general solution would be
Answer:
(1,2) is a solution to both equations
Step-by-step explanation:
To determine if (1,2) is a solution to both equations, substitute into the equation and see if it is true
2x+y =4
2(1) + 2 =4
2+2 =4
4=4
true
y =3x-1
2 = 3(1) -1
2 =3-1
2=2
true
Since both statements are true
(1,2) is a solution to both equations
Im sorry if I misunderstood the problem but heres my take.
Answer:
1155 for the cost of the people and 1250 for the total including the $95
Step-by-step explanation:
Multiply it ( 77 x 15 )
then add the answer to the $95 ( 95 + N )
= $N
Answer:
$216435
Step-by-step explanation:
Given : Suppose homes in a big city increase in value 13% every year.
To Find: How much will a home that cost $150,000 be worth 3 years later?
Solution:
Principal = $150000
Rate = 13% =0.13
Time = 3 years
Formula : ![A=P(1+r)^t](https://tex.z-dn.net/?f=A%3DP%281%2Br%29%5Et)
Now substitute the values in the formula
![A=150000(1+0.13)^3](https://tex.z-dn.net/?f=A%3D150000%281%2B0.13%29%5E3)
![A=216434.55](https://tex.z-dn.net/?f=A%3D216434.55)
So, The cost of home after 3 years will be $216435
Hence Option B is true