All categories

3 years ago

HELP!!! giving brainliest

Mathematics

1 answer:

Stolb23 [73]3 years ago

3 0

4cm = 5km

5/4 = 1.25

1cm = 1.25km

5 × 1.25 = 6.25

Hope this helps! :)

You might be interested in

It’s algebra 2! help asap plzz

san4es73 [151]

This is the difference of two perfect cubes.

(6y-4)(36y^2+24y+16)

3 0

2 years ago

Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)

Leni [432]

Step-by-step explanation:

3. The length of the rectangle is 3x and width is x+5

Now,

Area of rectangle=l×b

=3x(x+5)

=3x^2+15x(option d.)

4. 2/3x-4=20

2x/3=20+4

2x/3=24

2x=24×3

2x=72

x=72/2

x=36(option d.)

8 0

2 years ago

Read 2 more answers

What do you get when you cross a monastery with a lion

ivanzaharov [21]

<span>You get a roaring friar place!</span>

5 0

3 years ago

Need some help it'd be appreciated

Natalka [10]

Answer:

Step-by-step explanation:

The parallel postulate is one of Euclid main axioms. Since it was accepted as self evident.

A is wrong, any two points can be drawn a straight line through. And straight lines exist in plane geometry.

B and D is wrong, the angle measures of a triangle must add up to 180 degrees in plane geometry.

8 0

3 years ago

the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they

horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

$\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}$

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

5 0

1 year ago