−2x + 3y + 5z = −21
−4z = 20
6x − 3y = 0
do -4z=20 first
divide both sides by -4 to get z by itself
-4z/-4=20/-4
z=-5
Use z=-5 into −2x + 3y + 5z = −21
-2x+3y+5(-5)=-21
-2x+3y-25=-21
move -25 to the other side
sign changes from -25 to +25
-2x+3y-25+25=-21+25
-2x+3y=4
6x-3y=0
find x by eliminating y
Add the equations together
-2x+6x+3y+(-3y)=4+0
-2x+6x+3y-3y=4
4x=4
Divide by 4 for both sides
4x/4=4/4
x=1
Use x=1 into 6x − 3y = 0
6(1)-3y=0
6-3y=0
Move 6 to the other side
6-6-3y=0-6
-3y=-6
Divide both sides by -3
-3y/-3=-6/-3
y=2
Answer:
(1, 2, -5)
Answer: D
Step-by-step explanation:
1) Given: ds / dt = 3t^2 / 2s
2) Separate variables: 2s ds = 3t^2 dt
3) Integrate both sides:
∫ 2s ds = ∫ 3t^2 dt
s^2 + constant = t^3 + constant
=> s^2 = t^3 + constant
=> s = √ (t^3 + constant)
Answer: option B.
Answer:
TU=36
Step-by-step explanation:
use the side lengths of PQR to determine the proportionality of the two triangles. 9/2=4.5 so, multiply 8 by 4.5 to find TU.
Answer:
1. x=27
2. x=11 or x=-7
3. x=4
4. x=1 or 
5. x=12
6. x=11 or x=-1
7. x=8
8. x=3 or x=1
9. 
or x=-4
10.x=7 or x=1
Step-by-step explanation:
For the first 8, the absolute value portion is just substituted in for x, so we can skip some of the repeated work that would occur in these. For the absolute value problems, there are two solutions each. When you remove an absolute value, you have to add a plus or minus to each side and solve for each.
1. 
2. 
3. 
4. 
5. 
6. 
7. 
8. 
9. 
10. 
