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Price of one CD after February discount $

Mathematics

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Ksju [112]2 years ago

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Answer:

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Which two transformations are applied to pentagon ABCDE to create A’B’C’D’E’?

vesna_86 [32]

The pentagon was reflected across the x-axis. By looking at Point A, you can see x was increased 8, x+8. Also, y was increased by 2, y+2.

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The greatest common factor of 162, 378, and 414

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ella [17]

Answer:

Step-by-step explanation:

b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4 $x^{2}$

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3 years ago

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myrzilka [38]

I don’t understand your question

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3 years ago

Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationa

Artist 52 [7]

Answer:

Yes, they have the same solution.

Step-by-step explanation:

The steps in solving a two-step equation are to simplify by using

The inverse of addition or subtraction and then
The inverse of multiplication or division

Equation 1

$\dfrac{2}{3}x + \dfrac{3}{4} = 8$

(a) Inverse of addition

$\begin{array}{rcl}\dfrac{2}{3}x + \dfrac{3}{4} - \dfrac{3}{4}& = & 8 - \dfrac{3}{4}\\\\\dfrac{2}{3}x & = & \dfrac{29}{4}\\\end{array}$

(b) Inverse of multiplication

$\begin{array}{rcl}\left (\dfrac{2x}{3}\right ) \left (\dfrac{3}{2}\right ) & = & \left (\dfrac{29}{4}\right ) \left ( \dfrac{3}{2} \right ) \\\\x & = & \dfrac{87}{8}\\\end{array}$

Equation 2

8x = 87

(a) Inverse of multiplication

$\begin{array}{rcl}\dfrac{8x}{8} & = & \dfrac{87}{8}\\\\x & = & \dfrac{87}{8}\\\end{array}$

The two equations have the same solution.

For the first equation, I used the inverse of addition and then the inverse of multiplication to get the value of x.

The second equation needed only the inverse of multiplication.

Both solutions were the same.

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3 years ago