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11111nata11111 [884]
4 years ago
10

How many moles of solve (Ag) are equivalent to 68.3g Ag

Chemistry
1 answer:
Zina [86]4 years ago
5 0
Moles Ag = 68.3 g / 107.868 g/mol=0.633
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It may have twice as much electrons a the potassium ion.
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HELP PLS- One student made the incomplete diagram shown below to represent the relationship between magma, igneous rocks, and me
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According to the law of conservation of mass, what is the same on both sides of a balanced chemical equation?
Firlakuza [10]

According to the law of conservation of mass, what is the same on both sides of a balanced chemical equation?

A. the volume of the substances

B. the subscripts

C. the total mass of atoms

D. the coefficients

Answer:

A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.

Explanation:

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. ... Use coefficients of products and reactants to balance the number of atoms of an element on both sides of a chemical equation.

Consider the balanced equation for the combustion of methane.

CH

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2O

2

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CO

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O


All balanced chemical equations must have the same number of each type of atom on both sides of the arrow.


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C

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Here is a video that discusses the importance of balancing a chemical equation.

8 0
3 years ago
How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium
Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

  • HCl: 2 moles
  • Na: 1 mole
  • NaCl: 2 moles
  • H₂: 1 mole

You know the following masses of each element:

  • H: 1 g/mole
  • Cl: 35.45 g/mole
  • Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

  • HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
  • Na: 23 g/mole
  • NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
  • H₂: 2* 1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • Na: 1 mole* 23 g/mole= 23 g
  • NaCl: 2 moles* 58.45 g/mole= 116.9 g
  • H₂: 1 mole* 2 g/mole= 2 g

So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}

mass of H₂= 4.8 g

<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>

3 0
3 years ago
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