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Nataliya [291]
3 years ago
9

HELP PLS- One student made the incomplete diagram shown below to represent the relationship between magma, igneous rocks, and me

tamorphic rocks: three ovals, labeled from left to right, metamorphic rock, magma, and igneous rocks respectively. Which of these is the correct next step to complete the diagram? Put an arrow labeled cools and crystallizes, pointing from igneous rocks to metamorphic rocks. Put an arrow labeled cools and crystallizes, pointing from metamorphic rocks to igneous rocks. Put an arrow labeled heat and pressure, pointing from igneous rocks to metamorphic rocks. Put an arrow labeled heat and pressure, pointing from metamorphic rocks to igneous rocks.
Chemistry
2 answers:
Naya [18.7K]3 years ago
5 0

Answer:

ignious b

Explanation:

burns on lava rock

timama [110]3 years ago
3 0
Igneous rock because they form when hot, molten rock crystallizes and solidifies.
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Calories

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Greater absolute charge 
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A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

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Answer:

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Mechanical advantage is like a ratio of load to effort and many machines like pulleys depend on this relationship between load and effort for it to work.

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