By rewriting the weights in decimal form and applying them to the correspondent percentages, we will see that the final grade is 92.8%.
<h3>
What is Jore's final math grade?</h3>
The final grade will be given by:
G = a₁*x₁ + a₂*x₂ + ...
Where the values "a" are the weights, and the values "x" are the averages of Jeorge.
We know that the weights are:
- 30% on Quizzes.
- 10% on homework
- 40% on unit test.
- 20% on the final exam.
Then we can write the weights in decimal form:
a₁ = 0.3
a₂ = 0.1
a₃ = 0.4
a₄ = 0.2
And the scores are:
- 92% on quizzes.
- 98% on homework
- 91% on unit tests
- 95% on final exam.
So the final math grade will be:
G = 0.3*92 + 0.1*98 + 0.4*91 + 0.2*95 = 92.8%
If you want to learn more about percentages, you can read:
brainly.com/question/843074
Answer:
Step-by-step explanation:
It costs $7 for 1 baseball and Mrs.Weeks is buying 36 baseballs, that would be: $7 X 36 = $252
It costs $5 for 1 softball and Mrs.Weeks is buying 24 softballs that would be:
$5 X 24 = $120
$252 + $120 = $372 for the baseballs and softballs
Mrs.Weeks gives the cashier four $100 bills that is $400 dollars.
so $400 - $372 = $28 (Mrs.Weeks change)
<em>two hundred and eighty five</em>
Answer:
1 false
2 true
3 true
4 false
5 true
Step-by-step explanation:
f(a) = (2a - 7 + a^2) and g(a) = (5 – a).
1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial
When added together, they will be a second degree polynomial
2. true When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction
3. true f(a) + g(a) = (2a - 7 + a^2) + (5 – a)
Combining like terms = a^2 +a -2
4. false f(a) - g(a) = (2a - 7 + a^2) - (5 – a)
Distributing the minus sign (2a - 7 + a^2) - 5 + a
Combining like terms a^2 +3a -12
5. true f(a)* g(a) = (2a - 7 + a^2) (5 – a).
Distribute
(2a - 7 + a^2) (5) – (2a - 7 + a^2) (a)
10a -35a +5a^2 -2a^2 -7a +a^3
Combining like term
-a^3 + 3 a^2 + 17 a - 35
Answer:
88
Step-by-step explanation:
Given:
(h⁴ + h² – 2) ÷ (h + 3).
We could obtain the remainder using the remainder theorem :
That is the remainder obtained when (h⁴ + h² – 2) is divided by (h + 3).
Using the reminder theorem,
Equate h+3 to 0 and obtain the value of h at h+3 = 0
h + 3 = 0 ; h = - 3
Substituting h = - 3 into (h⁴ + h² – 2) to obtain the remainder
h⁴ + h² – 2 = (-3)⁴ + (-3)² - 2 = 81 + 9 - 2 = 88
Hence, remainder is 88
