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3 years ago

How to determine whether the pair of lines is parallel perpendicular or neither?

1 answer:

6 0

If the slopes of the 2 lines are equal then they are parallel.

If m1m2 = -1 (where m1 and m2 are the slopes of the 2 lines) then they are perpendicular.

If the 2 slopes do not match either the first or second conditions then they are neither parallel or perpendicular.

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Help me with this question, please, ill choose brainiest and give u 30 points for answering

Vsevolod [243]

Answer: D

Step-by-step explanation:

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3 years ago

A group of tenth grade students responded to a survey that was asked which Math course they were currently enrolled in. The surv

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Answer:

Step-by-step explanation:

The bottom-right most cell tells us that the total number of students that responded to the survey is 310 students.

To find the answer, we can go through each choice.

A. Females taking Geometry

Row 1 Column 2 tells us that 53 females are taking geometry. 53/310 is about 17%.

B. Females taking Algebra II.

Row 1 Colume 3 tells us that 62 females are taking Algebra II. 62/310 is 20%.

C. Males taking Geometry.

Row 2 Colume 2 tells us that 59 males are taking Geometry. 59/310 is about 19%. Choice C is correct.

D. Males taking Algebra I.

44 out of the total 310 respondents are male and is taking Algebra I. 44/310 is about 14%.

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3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

The volume of a sphere is V=4/3 pie r 3

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Answer:

A. 288pi in^3

Step-by-step explanation:

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2 years ago