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Answer:
100 J
Explanation:
From the question, The work done by the forces in moving the box is given as
W = FxdcosФ+Fydcosα................... Equation 1
Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.
Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°
Substitute into equation 1
W = 10×10×cos0°+5×20×cos90°
W = 10×10×1+0
W = 100 J.
Note: The work done by the perpendicular force is zero
Hence the work done = 100 J
F = 500N
S = 5m
T = 1.2s
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P = ?
We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12
So the final answer would be:
P = F * V = 500 * 50/12
Are you sure those are correct numbers? The answer don't look nice :D
