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vredina [299]
3 years ago
7

Which one of the following is a measurement of energy used?

Physics
2 answers:
Leokris [45]3 years ago
5 0

The correct answer to the question is D) 6 joules.

EXPLANATION:

As per the question, four measurements are given i.e 24 m/s, 60 mg, 15 L and 6 J.

We are asked to determine the measurement which corresponds to energy.

Energy is measured in various units like joule, erg, electron volt etc.

Joule is the unit of energy in S.I system.

Hence, the correct measurement which corresponds to energy is 6 joules.

All other measurements like 24 m/s, 60 mg and 15 L are not the measurements of energy. These are the measurements of speed, mass and volume respectively.




Lana71 [14]3 years ago
3 0
D. 6 Joules trust me i work with cars so i have to know this
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<span> We're given that x=25 when t=2: </span>

<span>25 = 3 + 12(2) + (1/2)a(2)^2 </span>

<span>Thus a = -1 cm/sec^2</span>
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When two plates of differing densities collide, how might the density of each plate affect which plate is pulled beneath the oth
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A total distance of 4.5km. The overall journey takes 0.62h, whats the average velocity
Westkost [7]

Answer:

7.3km/hr

Explanation:

v=d/t=4.5km/0.62hrs=7.3km/hr

6 0
3 years ago
Explain why it feels more forceful when you catch a baseball with your bare hand, as opposed to catching it with a glove.
Leona [35]

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your ball exherts more pressure on your hand because your hand is smaller then the glove. The pressure gets distributed a lot more when you catch it with your glove.

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5 0
2 years ago
What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of tempera
Nadusha1986 [10]

Answer:

The amount of energy required is 31.1692 kJ .

Explanation:

The transitions of water are as follows,

(243K ice to 273K ice to 273K water to 373k water to 373K steam to 393K steam)

The following required data is,

specific heat capacity of ice= 2.1 kJ/kg

specific heat capacity of water= 4.2 kJ/kg

specific heat capacity of ice= 1.996 kJ/kg

specific latent heat of fusion=334 kJ/kg

specific latent heat of vapourisation = 2260 kJ/kg

FORMULAS:-

temperature change=mc(T2-T1)

phase transistion = mL,

where, m=mass , c=specific heat capacity ,L = latent heat of fusion or vapourisation ,(T2-T1)= temparature change

Thus the total amount of heat is,

=mc(T4-T3) + mL + mc(T3-T2) + mL + mc(T2-T1)

=10(10^{-3} )(2.1)(30)+10(10^{-3} )(334)+10(10^{-3} )(100)(4.2)+10(10^{-3} )(2260) +10(10^{-3} )(20)(1.996)

=(0.3)(2.1) + (3.34) + (4.2) +  (22.6) + (0.2)(1.996)

=31.1692 kJ.

3 0
3 years ago
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