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Luden [163]
3 years ago
12

Fill in the blanks ....... combine features of both web apps and native apps​

Physics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

yvutvuvutvtyvyvtvytvtyvtvytvytvy

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Calculate the power required of a 60-kg person who climbs a tree 5 meters high in 10 seconds.
Alina [70]

Answer:

Explanation:

Power = Energy/time

-Don't have energy so I'm gonna solve for it

Gravitational Potential Energy = mass x gravity x height

= 60 kg x 9.8 m/s2 x 5m

= 2940 J

Power = Energy/time

=2940 J/10 s

= 294 W

3 0
2 years ago
An object accelerating may be changing in what two ways
Oksana_A [137]
Velocity and direction
8 0
3 years ago
Number 5 and 6 i need just give answer
sashaice [31]

Explanation:

voltage = current × resistance

5.

12 V = 4.2 A × resistance

resistance = 12 V / 4.2 A = 2.857142857... Ohm

FYI :

4.2 A would be a lot for a small electronic device like a CD player. that would be 12×4.2 = 50.4 Watt, and the CD player would get really hot.

6.

120 V = current × 12 Ohm

current = 120 V / 12 Ohm = 10 A

8 0
2 years ago
A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr
Zinaida [17]

Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

m'=9.00 \ g

or,

    =0.009 \ kg

mass of wooden block,

m=1.20 \ kg

speed,

s=0.390 \ m

Coefficient of kinetic friction,

\mu=0.20

As we know,

The Kinematic equation is:

⇒  v^2=u^2+2as

then,

Initial velocity will be:

⇒  u=v^2-2as

        =v^2-2 \mu gs

On substituting the given values, we get

⇒  u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}

       =\sqrt{-1.5288}

       =1.23 \ m/s

As we know,

The conservation of momentum is:

⇒  mu=m'u'

or,

⇒ Initial speed, u'=\frac{mu}{m'}

On substituting the values, we get

⇒                            =\frac{1.20\times 1.23}{0.009}

⇒                            =\frac{1.476}{0.009}

⇒                            =164 \ m/s                              

3 0
3 years ago
A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?
OLga [1]

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

7 0
4 years ago
Read 2 more answers
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