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2 years ago

Fill in the blanks ....... combine features of both web apps and native apps

Physics

1 answer:

natta225 [31]2 years ago

3 0

Answer:

yvutvuvutvtyvyvtvytvtyvtvytvytvy

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Which type of molecule is added to this genetic sequece might create a insertion mutation? A-G-A-T-G-C-A-G-A-G-T-T-A-C-G-G

Jet001 [13]

D. Adding another base pair will re-arrange your DNA sequences and cause an insertion mutation. This will make your codons group of differently, and possibly give you a BAD mutation. However, sometimes the codons still make the same proteins as its supposed to, the mutation will NOT affect you.

Example:

THE BIG FAT CAT ATE THE RAT

Now, if i were to add a letter (X) to this and make the letters group up in three aka the codons:

THE XBI GFA TCA TAT ETH ERA T

As you can you can see, adding a base pair in a DNA insertion will usually have a negative effect, specifically a insertion mutation.

3 0

3 years ago

What should a person do to reduce the risk of developing osteoporosis if it runs in the family?

Cerrena [4.2K]

Answer:

The <u>actual</u> answer would be A: Regularly engage in weight-bearing activities

Explanation:

Evidence can be seen in this article about osteoporosis-

8 0

2 years ago

Which has a higher acceleration: a 10-kg object acted upon with a net force of 20 N or an 18-kg object acted on by a net force o

Montano1993 [528]

The first one accelerate at 2m/s
the second one accelerates at 1.6666m/s

therefore statement b. the 10kg object is your answer

hope this helps :)

6 0

2 years ago

Read 2 more answers

A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?

Semenov [28]

Answer:

The maximum range $R_{max}= 132. 72$ m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

$R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }$ m

Where,

g - acceleration due to gravity

Substituting the values in the above equation

$R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }$

= 132.72 m

Hence, the car lands at a distance, $R_{max}= 132. 72$ m

3 0

3 years ago

Ball A (mass of 0.5 kg) going +2.0 m/s collides with a stationary ball B (mass of 0.4 kg).

ki77a [65]

The correct answer is 1.2 m/s

: mv+mv=mv+mv

(0.5kg)(2m/s)+(0.4kg)(0m/s)=(0.5kg)v+(0.4kg)(1m/s)

= 1kg*m/s=(0.5kg)v+0.4kg*m/s

=1kg*m/s-0.4kg*m/s=(0.5kg)v

=0.6kg*m/s=(0.5kg)v

to solve for v we divide both side by 0.5kg

v=1.2m/s

6 0

3 years ago

Fill in the blanks ....... combine features of both web apps and native apps​

Fill in the blanks ....... combine features of both web apps and native apps