Question

A force of 500 N is used to slide a box across a smooth surface; the box moved 5 m in 1.2 seconds. What power is used?

Answer 1

F = 500N
S = 5m
T = 1.2s
----------------------------------
P = ?

We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12

So the final answer would be:

P = F * V = 500 * 50/12

Are you sure those are correct numbers? The answer don't look nice :D

Answer 2

$Given:\\F=500N\\s=5m\\t=1.2s\\\\Find:\\P=?\\\\Solution:\\\\P= \frac{W}{t} \\\\W=Fs\\\\P= \frac{Fs}{t} \\\\P= \frac{500N\cdot 5m}{1.2s} \approx 2083.33W$