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3 years ago

HELP PLEASE ASAP 50 POINTS AND BRAINLIEST

Mathematics

2 answers:

Bad White [126]3 years ago

7 0

Answer:

Step-by-step explanation:

Margaret [11]3 years ago

6 0

Answer:

f(x+5)=(x+5)^2

=×^2+10x+25

y=×^2+10x+25

now substitute different values to x and start plotting the graph

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A microwave cost 200 plus 20% VAT what is the total price

iris [78.8K]

Answer:

Total price = 240

Step-by-step explanation:

a microwave cost = 200

20% of 200 = 20/100 x 200 = 40

total price = 200 plus 20% VAT = 200 + 40 = 240

7 0

3 years ago

The GCD(a, b) = 6, the LCM(a, b)=180. Find the least possible value of a+b.

julia-pushkina [17]

This is the concept of numbers, given that the G.C.D two numbers (a,b)=6 and the L.C.M (a,b)=180, to find the possible number we do as follows;
L.C.M =a*b=180
since 6 is a multiple of a and b, then the numbers could be:
180/6
=30
hence these numbers could be (6,30)

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3 years ago

Use the distributive property to simplify. 4(n-3)

Anvisha [2.4K]

Answer:

4n-12

Step-by-step explanation:

distribute 4 to the variable n and to 3

4 times n = 4n

4 times 3 = 12

4(n-3)=4n-12

3 0

4 years ago

Read 2 more answers

I need the answer to this

Marina86 [1]

Answer:

y = 6.5

Step-by-step explanation:

3 0

2 years ago

There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask

bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

$P(A)=\dfrac{40}{200}=0.2$

P(B) is the probability that the selected student plays basketball.

Then:

$P(B)=\dfrac{50}{200}=0.25$

P(A and B) is the probability that the selected student plays soccer and basketball:

$P(A\&B)=\dfrac{10}{200}=0.05$

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

$P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2$

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

4 0

4 years ago