Answer:

Step-by-step explanation:

If
than
and 

<u>⇒ Switch sides:-</u>
<u />
<u>⇒ Add 1 to both sides:-</u>
<u />

And...

<u>⇒ Add 1 to both sides:-</u>
<u></u>

<u>⇒ Now, Combine the intervals:-</u>
<u />
<u>OAmalOHopeO</u>
D for deprecated figures a hole of dc gg is liquid point a b c d e f g is it pick d on quiz or homework
Let
![I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint%20e%5E%7B-2x%7D%20%5Ccos%282x%29%20%5C%2C%20dx%5B%2F%5Dtex%3C%2Fp%3E%3Cp%3EIntegrate%20by%20parts%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdisplaystyle%20%5Cint%20u%20%5C%2C%20dv%20%3D%20uv%20-%20%5Cint%20v%20%5C%2C%20du)
with

Then

Integrate by parts again, this time with

so that

Answer:
30units,2900
Step-by-step explanation:
Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.
The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.
If x units are produced and sold we have
Costs for x units = variable costs *x +Fixed costs 
Sales revenue = no of units sold * price = 
Profit funciton = P(x) = Sales revenue - Total cost
= 
To get maximum profit we use derivative test I derivative =0 and II derivative =negative

Producing 30 units will maximize the profit.
Max profit
=P(30) = 2900