Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Answer:
sorry im not sure about the answer but this is how you figure it out
Step-by-step explanation:
50a+30b=550
after you simplify = 5a+3b=55
44a+36b=532
after you simplify=11a+9b=133
then you try to find a number
5a+3b=55
then you have to find different possibilities of a and b and if it can fit into both equations then it is correct
Answer:
12
Step-by-step explanation:
2x4=8
5x4=20
2x4=8
each side is multipled by 4
Answer:
441 seats are being used :]
Step-by-step explanation: