The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
Answer:
Apple
Orange
Step-by-step explanation:
Apple has the greater median with a median value of 150 which is more than that of orange at 130
The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.
Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.
2x + 3y = 630
x + y = 245 then you want to get rid of x so in the second equation × by -2 and get -2x -2y =-490 subtract this equation from the first to get y=$140 substitute 140 in for y and get x= $105 and 2x=210 and 3y=420 210 +420=630
Sample space ={5G, 2Y, 8R, 3P} =18 POSSIBLE OUTCOME
1st draw: P(R) = 8/18 = 4/9 = 0.444
2nd draw (no replacement, means already one Red is picked up, so the sample space has been reduced): P(another one more RED) = 7/17 =0.411
Literal or figurative language is the answer !
