First find the smallest value
You would need the smallest y value and the greatest x value
y = 10, x = 7
Therefore 10/7 would be the smallest
Now find the greatest
You would need the largest y value and the smallest x value
Y = 12, x = 6
Therefore 12/6 or 2 would be the largest
Solution: 10/7 < y/x < 2
64=2^6, 72=2^3*3^2
gcd (64,72)=8
Therefore 64/8 =8
72/8=9
gcd (8,9) =1
8,9 are relatively prime.
Thus, 64/72=8/9
Now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.
now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

Answer:(15, 100)
Step-by-step explanation:
first find the coordinates of the point above (3, 20)
you just look at the x axis and where the point is in this case x would be 6 and then you find y which would be 40
so the coordinate would be (6, 40)
now subtract (6, 40) by (3, 20)
6-3= 3
40- 20= 20
you get the first coordnites which is what you add (12,80) to
12 +3= 15
80+ 20= 100
you get the coordinates (15, 100)