Answer:
From what I know there is no q.
p=0 I put a slight explanation below.Hope it helps
Step-by-step explanation:
Ax^2+bx+c-p=x
Ax^2+bx+c-p-x=x-x
Ax^2+(b-1)x+c-p=0
Answer:
Step-by-step explanation:
Question (1).
OQ and RT are the parallel lines and UN is a transversal intersecting these lines at two different points P and S.
A). ∠OPS ≅ ∠RSU [corresponding angles]
B). m∠OPS + m∠RSP = 180° [Consecutive interior angles]
C). m∠OPS + m∠OPN = 180° [Linear pair of angles]
D). Since, ∠OPS ≅ ∠TSP [Alternate interior angles]
And m∠TSP + m∠TSU = 180° [Linear pair of angles]
Therefore, Option (A) is the correct option.
Question (2).
A). m∠RSP + m∠RSU = 180° [Linear pair of angles]
B). m∠RSP + m∠PST = 180° [Linear pair of angles]
C). ∠RSP ≅ ∠TSU [Vertically opposite angles]
D). m∠RSP + m∠OPS = 180° [Consecutive interior angles]
Therefore, Option (C) will be the answer.
Answer: 439.82
Step-by-step explanation:
C=2πr=2·π·70≈439.82297
There only 1 slope for (-3,5) (5,-3)
