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3 years ago

Please help I need to get this correct

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer: i think the answer is 2

Step-by-step explanation:

sorry if im wrong please forgive me

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Solve : sin 3x + cos 3x=0

klemol [59]

sin(3)+cos(3)sin(3)tan(3)3=0=−cos(3)=−1=−4+,∈ℤ=−12+3
sin⁡(3x)+cos⁡(3x) =0 sin⁡(3x) =−cos⁡(3x) tan⁡(3x) =−1 3x =−
π
4
+kπ,k∈
Z
x =−
π
12
+
k
π
3

Since −<<
−
π
<
x
<
π
, −2≤≤3
−
2
≤
k
≤
3
. Thus, the solution set is
{−34,−512,−12,4,712,1112}

4 0

3 years ago

Please answer number 5 thank you I give brainliest

Dovator [93]

Answer: 489.001

Step-by-step explanation:

Area equals length times width

5 0

3 years ago

Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago

Solve the inequality, -3 < n -8

vesna_86 [32]

Add 8 on both sides in order to isolate n:

-3 + 8 < n - 8 + 8

5 < n

8 0

3 years ago

Assume u4 is not a linear combination of {u1,u2,u3}

Feliz [49]

Answer:

A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.

Step-by-step explanation:

Given that u4 is not a linear combination of {u1,u2,u3}

This means there is no possibility to write u4 = au1+bu2+cu3 for three scalars a,b,and c.

This gives that $u_4-au_1-bu_2-cu_3 \neq 0$

This implies that these four vectors are not linearly dependent but linearly independent.

Hence option a is right.

A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.

8 0

3 years ago