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JulsSmile [24]
3 years ago
12

A drama club earns $1040 from a production. It sells a total of 64 adult tickets and 132 student tickets. An adult ticket costs

twice as much as a student ticket.Write a system of linear equations that represents this situation. Let x represent the cost of an adult ticket and y represent the cost of a student ticket.
Mathematics
2 answers:
STatiana [176]3 years ago
8 0
16x + 33y = 260, I think this is correct. Hope this helps!:)
Vika [28.1K]3 years ago
4 0
X= cost of adult tickets
x= 2y= cost of adult ticket
y= cost of student tickets

64 multiplied by the cost of an adult ticket plus 132 multiplied by the cost of a student ticket equals the total earned of $1040.

64x+132y= $1040
Substitute x=2y into equation
64(2y)+132y=1040
128y+132y=1040
260y=1040
Divide both sides by 260
y= $4 cost of student ticket

2y= cost of adult ticket
Substitute y=$4 to find adult cost
2(4)= $8 cost of adult ticket

Student ticket= $4
Adult ticket= $8

Hope this helps! :)

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Do I have to solve this before graphing it and if so how do I go about it?
defon

Given the System of Equations:

\begin{cases}y=4x-1 \\  \\ y=x-4\end{cases}

The exercise asks for solving it graphically. Then, in this case, you need to graph both lines in order to determine the solution of the system.

In order to graph it, you can find the x-intercepts and the y-intercepts:

1. It is important to remember the Slope-Intercept Form of the equation of a line:

y=mx+b

Where "m" is the slope of the line and "b" is the intercept.

In this case, you can identify that the y-intercept of the first line is:

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And the y-intercept of the second line is:

b=-4

2. By definition, the value of "y" is zero when the line intersects the x-axis.

Then, you need to substitute the following value of "y" into each equation and then solve for "x", in order to find the x-intercept of each line:

y=0

- For the first line, you get:

\begin{gathered} y=4x-1 \\ 0=4x-1 \\ 1=4x \\  \\ \frac{1}{4}=x \\  \\ x_1=0.25 \end{gathered}

- For the second line, you get:

\begin{gathered} y=x-4 \\ 0=x-4 \\ 4=x \\ x_2=4 \end{gathered}

3. Now you know that the first line passes through these two points:

(0.25,0);(0,-1)

And the second line passes through these two points:

(4,0);(0,-4)

4. Knowing those points, you can graph the lines:

Notice that the line intersect each other at

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(15, -8) :)
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