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kogti [31]
3 years ago
15

SOMEONE HELPPP THANKYOUU

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

5(8 - 2t) = 2 + 16(4 + t)

open the brackets;

use 5 to mulitiply (8 - 2t) = 40 - 10t

use 16 to mulitiply (4 + t) = 64 + 16t

then we have 40 - 10t = 2 + 64 + 16t

collect like terms

40 - 2 - 64 = 16t + 10t

-26 = 26t

divide both sides by 26

t = -1

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3 0
3 years ago
Read 2 more answers
Which equation represents a parabola that opens upward, has a minimum at x = 3, and has a line of symmetry at x = 3?
densk [106]

Answer:

A.\ y = x^2 - 6x + 13 is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

y = a(x-h)^2+k

where (h,k) is the vertex of the parabola and

(x,y) are the coordinate of points on parabola.

As per the question statement:

The parabola opens upwards that means coefficient of x^{2} is positive.

Let a = +1

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

\therefore h = 3

Putting value of a and h in the equation:

y = 1(x-3)^2+k\\\Rightarrow y = (x-3)^2+k\\\Rightarrow y = x^2-6x+9+k

Formula used: (a-b)^2=a^{2} +b^{2} -2\times a \times b

Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.

Comparing y = x^2 - 6x + 13 and y = x^2-6x+9+k

13 = 9+k

k = 4

Please refer to the graph attached.

Hence, correct option is A.\ y = x^2 - 6x + 13

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3 years ago
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