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Anna007 [38]
3 years ago
10

The graph shows the distances traveled by two buses.

Mathematics
2 answers:
juin [17]3 years ago
7 0

<u>Answer-</u>

<em>The equation that could represent the distance traveled by Bus B is </em><em>y = 40x</em>

<u>Solution-</u>

On abscissa time in hour is represented and on ordinate distance in km is represented.

The equation for Bus A is given by,

y=55x

Comparing it with the general slope-intercept equation of straight line,

y=mx+c

Where,

m = slope = 55

c = y-intercept = 0

We know that slope is measured as the tangent of the angle made by the line with positive x-axis measured in counter-clockwise direction.

Slope for Bus A = m₂ = tan θ₂

Slope for Bus B = m₁ = tan θ₁

From the properties of trigonometric function,

\Rightarrow \tan \theta_1

From the given option, only the first option has a straight line equation with slope less than m₂ or 55, which is 40.

Therefore, the equation that could represent the distance traveled by Bus B  is y = 40x

zalisa [80]3 years ago
4 0

Answer:

y=40x

I've done the test and this was correct.

hope it helps :)

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The perimeter of a rectangle is given by the formula P = 2(l + w), what is the value of P if l = 2 cm and w = 1/2 cm?
Sonja [21]

Answer:

\large\boxed{C)\ 5cm}

Step-by-step explanation:

P=2(l+w)\\\\\text{Put}\ l=2cm\ \text{and}\ w=\dfrac{1}{2}cm\ \text{to the formula of the perimeter:}\\\\P=2\left(2+\dfrac{1}{2}\right)=(2)(2)+(2)\left(\dfrac{1}{2}\right)=4+1=5\ cm

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3 years ago
What is the solution set of x^2+y^2=26 and x-y=6
Strike441 [17]
x^{2} + y^{2} =26  x-y=6  x=y+6&#10; Replacing in equation;  (y+6[tex] )^{2}+y^{2}=26
y^{2} +12x+36+ y^{2} =36
=2y^{2} +12x+36-26=0
=2y^{2} +12x+10=0
Product = 12
Sum= 10
factoring;
2y^{2}+2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1

4 0
4 years ago
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15. Before and after experiments, those that nse the same subjects for pre-testing and post-testing a treatment,
BabaBlast [244]
The answer would be E
3 0
3 years ago
Indiras spring garden has half as many tulips as daffodils and three times as many hyacinths as tulips. If there are a total of
kow [346]

Indira is having 34 tulips, 68 daffodils and 102 hyacinths , altogether 204 flowers in her spring garden.

Given, In Indira's springtime garden, there are three times more hyacinths than tulips and half as many daffodils as tulips.

let the number of tulips be = x

    the number of daffodils be = y

    the number of hyacinths be = z

hence according to the question,

tulips are (x) = 1/2 (y) = y/2

hyacinths are (z) = 3(x) = 3x

therefore, total flowers = 204

tulips ₊ daffodils ₊ hyacinths = 204

y/2 ₊ y ₊ 3x = 204

substitute x value in the above equation.

y/2 ₊ y ₊ 3(y/2) = 204

take LCM

y ₊ 2y ₊ 3y = 408

6y = 408

y = 408/6

y = 68

hence the number of daffodils is 68.

now substitute y value in x = y/2

x = 68/2

x = 34

now substitute x value in z= 3x

z = 3(34)

z = 102

hence we get the number of tulips,daffodils and hyacinths as 34 , 68 and 102 respectively.

Learn more about Solving equations here:

brainly.com/question/13729904

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6 0
1 year ago
Center : (0,0) radius=11
Klio2033 [76]

Answer:

is there a image if so put it there so i can answer

Step-by-step explanation:


7 0
3 years ago
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