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loris [4]
3 years ago
8

Determine which one of the following statements is true.

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

<u>D. Exponential growth will always exceed linear growth.</u>

Step-by-step explanation:

An "exponential growth function" would always exceed the "linear growth function" in the end because the "x-values" tends to get larger in continuation, so the change rate associated with the "exponential function" also increases in continuation whereas the "linear functions' change rate is considered as constant.

<u>In the question above, option D is correct. </u>

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A 13?-foot board is cut into two pieces. The longer piece is 7.5 feet longer than the shorter piece. What is the length of each?
chubhunter [2.5K]

Answer:

The smaller board would be 2.75 feet and the longer one would be 10.25 feet.

Step-by-step explanation:

In order to find this, assume the shorter board is equal to x. Next, we would know that the longer board would be equal to x + 7.5. Using these two assumptions, we can add the lengths together, set equal to 13 and then solve for x.

x + (x + 7.5) = 13

2x + 7.5 = 13

2x = 5.5

x = 2.75

Now that we have the length of the shorter board, we can add 7.5 to it to get the larger one.

2.75 + 7.5 = 10.25

6 0
4 years ago
Express 0,45 as a common fraction in simplest form
Bezzdna [24]
In order to express 0.45 as a common fraction, all you have to do is first divide 45 to 100. So in order to get the answer to this, you just have to put 45 as the numerator and 100 as the denominator. This will become 45/100. To turn it into its simple form, you have to first ask yourself what is a common divisible number for the two. 5 can be divided by 45 and 100 so 5 can be used. So the final answer, if you make it into simplest form, will be 9/20
8 0
3 years ago
Read 2 more answers
For each table, determine whether it shows that x and y are proportional.
myrzilka [38]

9514 1404 393

Answer:

  1. proportional, 6

  2. not proportional

Step-by-step explanation:

<u>Table 1</u>

Each y-value is 6 times the corresponding x-value, so the variables are proportional, and y = 6 times x.

<u>Table 2</u>

The ratios of y to x are 2, 4, 8, so are not the same. The values are not proportional.

8 0
3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
What does 49.39 round to.
Verizon [17]
If you want to round 49.39 to the nearest tenths place you will have to look at your tenths digit. The digit is 3, right? Look at the next number after 3. It is the number 9 for the hundredths place. If the number is bigger than 5 you round it. If it is smaller, you keep it the same. 9 is bigger than 5 so you make the 3 into a 4. Then, you're answer is 49.4 or 49.40 (Which are basically the same answer) It also works the same with the other digits. Simple, right? :)
4 0
3 years ago
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