Answer:
48
Step-by-step explanation:
here, we are using an = ar^n-1
so, we have to find a4= ar^4-1 = ar^3
now, putting the given values in the equation,
a4= (6)(2)^3 = 6(8) = 48
therefore, the 4th term is 48.
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10, because then meg would have 5.
Answer:
Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.
Step-by-step explanation:
<u>Dada la siguiente información:</u>
<u></u>
Cantidad de cajones= 300
Opción A:
Camiones con capacidad para 50 cajones que cobran 150 por viaje.
Cantidad de camiones= 300/50= 6
Opción B:
Camiones con capacidad de 60 cajones por 180 por viaje.
Cantidad de camiones= 300/60= 5
<u>Debemos calcular el costo total de cada opción y elegir la de menor costo.</u>
Costo total A= 150*6= $900
Costo total B=180*5= $900
Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
Answer:
Figure 1
Step-by-step explanation:
3^+ 4^-7/2=8
