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mezya [45]
3 years ago
12

I need help, what does this mean

Mathematics
1 answer:
GaryK [48]3 years ago
6 0
You have write a fraction from the figure.
In the numerator you have write the total of shaded boxes (in the second figure: 6) and in the denominator you have to write the total of boxes ( in the second figure: 10)
So the answer is 6/10 and this makes sense because this represents the same fraction from first fraction
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A regular Pentagon with sides 40cm what is the perimeter​
grigory [225]

Perimeter = namely the length of outside bordering,

well, this is a PENTAgon, or PENTA=5 or namely 5 sides, is regular so each side is the same length, so we have a polygon with 5 sides each measuring 40cm, well, its perimeter is just 40+40+40+40+40 = 200.

7 0
3 years ago
Desiree ran 12 miles in 1 hr, 48 minutes, What was Desiree's average running rate, in minutes per mile
Rina8888 [55]

Answer: 1/9

Step-by-step explanation:

60 + 48 = 108 minutes

12 / 108 = 1/9

3 0
3 years ago
Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?
Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: y = 3 \cos(10 (x -\pi))

We can assume the parent function to be:

y = \cos (x)

The new function can be represented as:

y = A*\cos((\frac{2\pi}{B})(x-c))

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

y = A*\cos((\frac{2\pi}{B})(x-c)) to y = 3 \cos(10 (x -\pi))

A = 3

c = \pi

\frac{2\pi}{B} = 10

Solve for B

B = \frac{2\pi}{10}

B = \frac{\pi}{5}

Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

  • <em>Vertically stretched by </em>3<em />
  • <em>Horizontally compressed by </em>\frac{\pi}{5}<em />
  • <em>Right shifted by </em>\pi<em />
5 0
3 years ago
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please HELPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Anni [7]
1/2!!! hope this helps!
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3 years ago
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Help needed for some geometry
Y_Kistochka [10]
In order to create a line parallel to line “I”, rotate line “I” 180° about points “F”. This can be done clockwise or counterclockwise.
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3 years ago
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