This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
i^0 = 1 . . . . . as is true for any non-zero value to the zero power
i^1 = i . . . . . . as is true for any value to the first power
i^2 = -1 . . . . . from the definition of i
i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4
1. = -3^4·i^(3·2+0+2·4) = -81·i^14 =
812. = i^((3-5)·2+0 = i^-4 =
13. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 =
4i4. = i^(3+(2+3+4+0+2+5)·2) = i^35 =
-i
8x^2 plus 8x , use the box method ! It is very helpful for area and any other multiplication
A linear function that has a slope of -3/4 is parallel to the given function
9514 1404 393
Answer:
top-down
f(g(x)) = 1, 4, 5, 3, 2
g(f(x)) = 5, 2, 4, 1, 3
Step-by-step explanation:
To find f(g(x)), locate g(x) in the third column (labeled g(x)). Use that value as x in the first column, then read f(x) from the second column.
Example: f(g(1)) = f(2) = 1
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To find g(f(x)), locate f(x) in the second column (labeled f(x)). Use that value as x in the first column, and read the corresponding g(x) from the third column.
Example: g(f(1)) = g(2) = 5
V=4/3πr^3
36π=4/3πr^3
3/4(36π)=(4/3πr^3)3/4
27π=πr^3
π(27π)=r^3
27=r^3
square root
r=3
s.a=4πr^2
s.a=4π(3^2)
s.a=4π(9)
s.a=36π