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4 years ago

(4/5 -7/5) + 1/5= Please hurry

Mathematics

1 answer:

ladessa [460]4 years ago

3 0

it is = -0.4, negative zero point four

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What is 4.75=X+60.25)

Alexandra [31]

Answer:

x=-55.5

Step-by-step explanation:

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4 years ago

X^2-48=(x-b)(x+b), what's the value of 'b'

allochka39001 [22]

X^2-48 can be viewed as a difference of squares which would factor to:

(x+√48)(x-√48)

So b=√48

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3 years ago

Find the circumcenter of triangle EFG with E(3,6), F(3,4), and G(7,4).

MrRissso [65]

$\Delta\ EFG\ is\ right\ triangle\ :)\ (look\ at\ the\ picture)\\\\Circumference\ of\ right\ triangle\ is\ in\ the\ middle\ of\ the\ hypotenuse\ (EG).\\\\C\left(\frac{3+7}{2};\ \frac{6+4}{2}\right)\to\boxed{C(5;\ 5)}$

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4 years ago

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

cestrela7 [59]

Answer:

$P(E_1 or E_2) = \frac{7}{12}$

Step-by-step explanation:

Given

Two cubes of side 1 - 6

Required

Probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5

First, the sample space needs to be listed;

Let $C_r$ represent the Red cube

$C_b$ represent the Blue cube

S represent the sample space

$C_r = (1,2,3,4,5,6)\\C_b = (1,2,3,4,5,6)\\S = (2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12)$ S is gotten by getting the sum of $C_r$ and $C_b$

$n(S) = 36$

<em>Calculating the Probability</em>

Let $E_1$ represent the event that an outcome is an odd sum

$E_1 = (3,5,7,3,5,7,5,7,9,5,7,9,7,9,11,7,9,11)$

$n(E_1) = 18$

$P(E_1) = \frac{n(E_1)}{n(S)}$

$P(E_1) = \frac{18}{36}$

Let $E_2$ represent the event that an outcome is a multiple of 5

$E_2 = (5,5,5,5,10,10,10)$

$n(E_2) = 7$

$P(E_2) = \frac{n(E_2)}{n(S)}$

$P(E_2) = \frac{7}{36}$

Let $E_3$ represent the event that an outcome is an odd sum and a multiple of 5

$E_3 = E_1 and E_2$

$E_3 = (5,5,5,5)$

$n(E_3) = 4$

$P(E_3) = \frac{n(E_3)}{n(S)}$

$P(E_3) = \frac{4}{36}$

Calculating $P(E_1 or E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_1 and E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_3)$

$P(E_1 or E_2) = \frac{18}{36} + \frac{7}{36} - \frac{4}{36}$

$P(E_1 or E_2) = \frac{18 + 7 - 4}{36}$

$P(E_1 or E_2) = \frac{21}{36}$

$P(E_1 or E_2) = \frac{7}{12}$

Hence, the probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5 is $\frac{7}{12}$

6 0

3 years ago

A rectangular prism has a length of 1 1/2 feet, a width of 2 1/2 feet, and a height of 8 feet. what is the volume of the prism i

statuscvo [17]

The volume of a rectangular prism is the product of its length, width, and height.
V = LWH
V = (1.5 ft)(2.5 ft)(8 ft)
V = 30 ft³

The volume of the prism is 30 cubic feet.

8 0

4 years ago