We can calculate the new volume of the gas using the Combined Gas Law:
(P1 x V1) / T1 = (P2 x V2) / T2
The initial volume, pressure, and temperature were 280 mL, 1.3 atm, and 291.15 K (changing the temperature into Kelvin is necessary), and the final volume, pressure, and temperature is V2, 3.0 atm, and 308.15 K. Plugging these values in and solving, we find that:
(P1 x V1) / T1 = (P2 x V2) / T2
(1.3 atm x 280 mL) / 291.15 K = (3.0 atm x V2) / 308.15 K
V2 = 128.42 mL
This makes sense considering the conditions, a small increase in temperature would make the gas expand but a significant increase in the pressure would cause the volume to decrease.
Hope this helps!
Answer:
Q = 1379.4 J
Explanation:
Given data:
Mass of water = 22 g
Initial temperature = 18°C
Final temperature = 33°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.
°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33°C - 18 °C
ΔT = 15°C
Q = 522 g ×4.18 J/g.°C× 15°C
Q = 1379.4 J
I can see two answers, I’d go with D, but all neutral atoms, of the same element would have the same number of outer electrons. However, if you consider that some of the atoms might be ions, that would eliminate B.
