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nika2105 [10]
3 years ago
11

Calculate the volume of a cube with links to 2.2 in.

Chemistry
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

10.65

Explanation:

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How many liters of space will 7.80 moles of methane gas (CH4) occupy at STP
Alchen [17]

Answer:

V CH4(g) = 190.6 L

Explanation:

assuming ideal gas:

  • PV = RTn

∴ STP: T =298 K and P = 1 atm

∴ R = 0.082 atm.L/K.mol

∴ moles (n) = 7.80 mol CH4(g)

∴ Volume CH4(g) = ?

⇒ V = RTn/P

⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)

⇒ V CH4(g) = 190.6 L

4 0
3 years ago
A pharmaceutical company is making a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount
iragen [17]

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100

Now We can obtain the percent yield as followed using the above formula:  

\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times  100

47\% = \frac{Actual \ yield \ Rate}{4860}

The value of the Actual yield Rate =47\% \times 4860

                                                        = \frac{47}{100} \times 4860 \\\\ = 2284.2 g

The Actual yield Rate= 2284.2 g.

3 0
2 years ago
Which question would most likely be studied by a chemist?
lbvjy [14]

Answer:

fd

Explanation:

fff

3 0
3 years ago
Normal red blood cells slide easily through narrow blood vessels. In sickle cell disease, many red blood cells change to a cresc
dybincka [34]

Answer:

C. The child must have inherited sickle cell genes from both parents.

Explanation:

Because of the fact that sickle cell disease is recessive, the child would have to get the gene from both parents.

8 0
2 years ago
Read 2 more answers
2Al+3Cl2⟶2AlCl3
Leviafan [203]

Answer:

7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.

Explanation:

Given data:

Moles of Al = 4.89 mol

Number of moles of Cl₂ required = ?

Solution:

Chemical equation:

2Al + 3Cl₂    →   2AlCl₃

Now we will compare the moles of Al and chlorine from balance chemical equation.

                            Al           :         Cl₂

                             2           :           3

                            4.89      :         3/2×4.89 =7.335 mol

Thus, 7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.        

8 0
2 years ago
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