The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)
<h3>Balanced equation </h3>
4Hg + O₂ —> 2Hg₂O
From the balanced equation above,
4 moles of Hg reacted with 1 mole of O₂
<h3>How to determine the limiting reactant</h3>
From the balanced equation above,
4 moles of Hg reacted with 1 mole of O₂
Therefore,
12 moles of Hg will react with = 12 / 4 = 3 moles of O₂
From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.
Thus, Hg is the limiting reactant and O₂ is the excess reactant .
Learn more about stoichiometry:
brainly.com/question/14735801
#SPJ1
Answer:
Ships traveling through the ocean
Answer:
The structure can be found on the attached documents
Explanation:
Answer:
See explanation and image attached
Explanation:
A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.
The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.
Answer:
was difficult to place isotopes of elements as they have the same chemical properties but different atomic masses. It was not possible to predict how many elements could be discovered between two heavy elements as the rise in atomic mass is not uniform.