The precipitate that forms when aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate.
Barium Nitrate is a colorless to white, odorless, crystalline powder. It is used in making fireworks, for green lights and neon lights, and in ceramic glazes.
Sodium Sulfate Anhydrous is the anhydrous, sodium salt form of sulfuric acid. Sodium ion is the principal cation of the extracellular fluid and plays a large part in the therapy of fluid and electrolyte disturbances.
When aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate, one soluble salt, sodium nitrate, and an insoluble salt, barium sulphate.
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Every isotope of an element has a different number of neutrons, which means that the atomic property which is different in each isotope of an element is mass number.
Mass number depends on the number of neutrons in an element.
The volume of ethyl alcohol overflow will be 9.265mL.
To calculate the volume of ethyl alcohol overflow, we will use
∆V=V(á∆T)
Where,
∆V=volume expand
á=volumetric expansion Coefficients =0.00109/°C
V=initial volume =500ml
T'=final temp. =22°C
T=initial temp=5°C
Now,
∆V=500×(0.00109/°C) ×(22-5)
=500×(0.00109) (17)
=9.265ml
Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.
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Answer:
1.78 atm
Explanation:
From the question given above, the following data were obtained:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Volume (V) = 70.0 L
Temperature (T) = 30 °C
Pressure (P) =?
Next, we shall determine the number of mole in 355 g of chlorine (Cl). This can be obtained as follow:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Mole of Cl =.?
Mole = mass /molecular weight
Mole of Cl = 355 /70.9
Mole of Cl = 5 moles
Next, we shall convert 30 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 30 °C
Temperature (T) = 30 °C + 273 = 303 K
Finally, we shall determine the pressure of the gas as illustrated below:
Volume (V) = 70.0 L
Number of mole (n) = 5 moles
Temperature (T) = 303 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 70 = 5 × 0.0821 × 303
P × 70 = 124.3815
Divide both side by 70
P = 124.3815 / 70
P = 1.78 atm
Therefore, the pressure of the gas is 1.78 atm
Answer: Option (d) is the correct answer.
Explanation:
It is given that mass of 
is 137.0 g.
Molar mass of is as follows.
Molar mass of = 2 × 14 + 3 × 16
= 76 g
Thus, number of moles will be calculated as follows.
No. of moles = 
= 
= 1.803 mol
There are 2 nitrogen (N) atoms present in the formula of dinitrogen trioxide. Also Avogadro's number equals 
atoms or molecules per mol.
Therefore, number of N molecules or atoms in is as follows.
Number of N atoms = 
= 
atoms
= 
atoms
Thus, we can conclude that there are atoms of N in in 137.0 grams of .
