Answer:
Please see explanation for the answer. The code is written in python and is as given below:
Step-by-step explanation:
The solution is obtained on the Python with the following code
import matplotlib.pyplot as plotter
import numpy as npy
x_s = npy.linspace(-5,5,100) #Defining a linear sample space with boundaries as -5 to 5 and 100 as number of samples.
def sigmo(z):return 1/(1 + npy.exp(-z)) #Defining sigmoid function for the f(x).
plotter.plot(x_s, sigmo(x_s))
plotter.plot([-5,5],[.5,.5])
plotter.xlabel("z")
plotter.ylabel("sigmoid(z)")
plotter.show()
Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be
Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Answer:
Step-by-step explanation:
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